The average bill for car repairs at a car service center is $196, with a standard deviation of $44. Assuming the bills to be normally distributed, find the probability of a bill exceeding $300.
for normal distribution z score =(X-μ)/σ | |
here mean= μ= | 196 |
std deviation =σ= | 44.0000 |
probability of a bill exceeding $300 =P(X>300)=P(Z>(300-196)/44)=P(Z>2.36)=0.0091
The average bill for car repairs at a car service center is $196, with a standard...
The average bill for car repairs at a car service center is $196, with a standard deviation of $44. Assuming the bills to be normally distributed, find the probability of a bill exceeding $300. Group of answer choices 0.4909 0.0182 0.9819 0.1406 0.0090 A tire manufacturer believes its tires will last an average of 48,000 miles, with standard deviation of 2,000 miles. What is the probability that one of these tires, chosen at random, will last at least 50,000 miles?...
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