Following is the - complete; Answer -&- Explanation: for the given: Question: in....typed format...
Answer:
Explanation:
Following is the complete Explanation: for the above: Answer.
Using the Calusius-Clapeyron Equation: we can derive the following Equation:
ln ( P1 / P2 ) = - Hvap / R x ( 1/ T1 - 1/T2 ) -------------------------------Equation - 1
Where:
Now, plugging in values: in : Equation - 1, we would get, the following:
( 1/ T1 - 1/T2 ) = 0.0007074
( 1/ 298 - 1/T2 ) = 0.0007074
1/T2 = 0.002648
T2 = 377.6 K = ( 377 - 273 ) = 104.6 oC
Therefore: Calculated normal boiling point of water : Tbp = 104.6 oC
We know: accepted value of boiling point of water = 100.0 oC
Here, the calculated value of the boiling point of water, is slightly more than the accepted value, because: the values used above: depends on the value of enthalpy of vaporization, and the value of vapor pressure at 298 K , which may have some errors. Due to the above said errors, the calculated value of the normal boiling point of Water, may vary from : the accepted value: of normal boiling point of Water...
2. (a) Using data commonly found on the Internet about the properties of water, calculate the...
2. (a) Using the data commonly found on the internet for the properties of water, calculate the normal boiling point of water at 1 bar. (b) What are some possible reasons that your answer may differ from the accepted value of 100 °C?
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