Question

The vapor pressure of benzene is found to obey the empirical equation torr T T2 In (P) = 16.725 – 3229.86 K _ 118345 K? from 298.2 K to its normal boiling point 353.24 K. Given that the molar enthalpy of vaporization at 353.24 K is 30.8 kJ mol-1 and that the molar volume of liquid benzene at 353.24 K is 96.0 cm3 mol-1, use the above equation to determine the molar volume of the vapor at its equilibrium pressure at 353.24K and compare this value with the ideal- gas value.

Answer 1

get From clausius clapeyron anation we A Feitin --- ashere, Atwap - Heat of vaporisation Ta temperature at kelvin a change of raper foressure It with respect to change. of temperature Va volume of gaseous state &- volume of liquid state Here given canation 118305 kr = 16.725 - 3229.86k T 72 .. wow, doing derivative of canation (ii) den (estuur) -- o + 3229.86K - (2 x 18345) &T T3 3229.86k sen (Cltore) +2366 90 km T3 72 236690 n. de PaT 32,29.86k T 73 ridlox T2 7 P . 322986K + 234690** lap) - Px[3.229.5e A, 23494) - en - V) 32,29-36K + 292090 **) everyone I say son # 2391 xy ?

t 23 669042 Ahvap 32,29.86 k 7 A liquid start to buit at it's atmospheric pressure is.polarm - 760 ton. This happened at normal boiling state. So, here, p= 760 toor, T=353.24K Atrap 30.8k1 mot' = 30800 Image =? ; V- 96.0 con molt = 96.0 x 1lt 100ocuz mest = 0.096 Lt moll tere, / 11 = 7.5 Lt ton) Atrop à 30800 I mein = 30800 x7.5 Lt tom. moll 3229 86k = 23,000 Lt torr most pluggin all the values into eanation (ii) 231000 Lt door mos 76store - 0.096 Lt mos ) - 353.244 + 23 6690 kr 353.244) 231 ooolt tofs molt = 839 0.71 ter - 0.0964 mon = 231000 Lt mit 8390.714 - 0.096 ir mein = 231 000 Lt mot von d. 0964t wor! 83907 7 27.53 Lt mort ave – 0.0964+ more V = (27.53 0.096) et mort = 27.626 Lt mort : molar volume of a vapor = 27.6 26 Lamas

According to ideal gas et STP. il. 273. 154 & s. atm = 760 tor . mole of ideas gan acill occupy 22.4 Lt. where, So, using P = P24 (1,- Peities pressure, have, P = 760 torr P2= Final Pressure P2 = 760tour To Iritial eup - 22.4 et mort V2 -?30 Ta final temp = 273.156 . V dnitial T= 353.24 K vol VF Final voll 760 X 22.4 . - 760X V 273.15 353.24 2 x 3 53.2 ý 7 60 .: V 780 x 22.9 7 273-15 X درها 2 ° . According to ideal gan value it showd be 28.96 Lt mon but here 27-62644 mort at 353.24k