Question

B and D please

4. Starting from rest, a basketball rolls from the top to the bottom of a hill, reaching a translational speed of 6.30 m/s. Ignore frictional losses. 6.30 m/s a) Which moment of inertia formula best represents the basketball? (3 pts) b) What is the height of the hill? (6 pts) 1-23 MR² & 3 mugh the I ugarigh hour = 2mgnan Žmorte 1 (3 m²) (7) since I way ghzu2(5/6) Ź (m + 2 vaugh a 9h 25 g 2 (mitte juce z hout2=2382 16.30 mth c) Which moment of inertia formula best represents a can of frozen juice? (3 pts) 23.5 m a can of frozen Surces I = 12 mL I = 1 / mp3 dB d) Released from rest at the same height as the basketball, a can of frozen juice also rolls to the bottom of the same hill. What is the translational speed of the frozen juice can when it reaches the bottom? (6 pts) WN - mua ² + + I wp? - ngh v=5366.50) in vrt (1)) (wi) va = amgh 2 (mu) v 1² nigh 37 mitte 2 ( m uch 6 = 3.14 mare

Answer 1

Parte tnmshion Ehng7 mgh mvt inudhia Hollow' Sphen 6 9.8 h 3.375 M momendo inetaf Cm - V timetind mvt mgh Jh-! g-8x3.33 S=2)v Viady,V 64 ms Veboc at batenz (-64