here this is binomial distribution with parameter n=3 and p=probability of getting right answer =1/5 =0.2
a)
P(X=3)=3C3(0.2)3(0.8)0 =0.008
b)
P(X=0)=3C0(0.2)0(0.8)3 =0.512
c)
P(X=1)=3C1(0.2)1(0.8)2 =0.384
d)
P(X=2)=3C2(0.2)2(0.8)1 =0.096
e) sum of above probabilities=0.008+0.512+0.384+0.096 =1
Exercise 3.10. Guessing on an exam. While taking a probability exam, you come to three questions...
Exercise 3.10. Guessing on an exam. While taking a probability exam, you come to three questions that you have no clue how to answer. You would have known the answers if you had taken the time to study the night before instead of going to a party, but you did not make a good life choice, and you vow to never party on a school night again if you fail this exam. Each question on the exam is multiple choice...
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