Lindlar's catalyst H- HC H-C-cEc-CHs h) HgSo, HC-HC-c c-H it + Н,о H,SO amu O HyCHC-cc-CH +H.O Н С k) 1. КОН HyC HC-CC CH hot KMnO 2. HC H,C HC CEC CHy cold KMnO Lindlar's catalyst H- HC H-C-cEc-CHs h) HgSo, HC-HC-c c-H it + Н,о H,SO amu O HyCHC-cc-CH +H.O Н С k) 1. КОН HyC HC-CC CH hot KMnO 2. HC H,C HC CEC CHy cold KMnO
draw the product 20. 0 H,C 21. soch 0 CH,OH 0 1 . LiAlH4, ether 2 H3o CH, 24. CHCH-C-a+ 25. 0 0 OH al 26. OCH, HC
CHGOH c=o OH H- C=0 HOW H- OH Ho+H HOM онон H CH.CH CH OH CH OH sorbose xylulose wylo D isomer L isomer OH OH CH3 -CH-CH CH-CH CH3 -CH2-C-CH3 CH Scree 2019-12 Chiral Achiral Student F ion_Han...
Canvas Glve the product of the reaction. 1. POL CH.CH OH 2 2 (CH O CH,HCI CH.CH CH O .CH (CH4, ci CH,CHE N Сн, CHE + Сн, но CH.CH CH, H Сн,онун, с CH.CH CH.CH 0 + (он, но CH SAMSUNG CH
1 Ó 1) HC =c- 2) H,0 I CH Determine the product но с o=1-0 OH HCTH HH H. CH HH
HO CH сн. CH2 нс HC CH3 HAC-HC CH CH CH CH d) OH OH 13. The labels have fallen off three bottles. Bottle A contains a gas, bottle B contains a liquid, and bottle C contains a solid. The labels indicate that the compounds have the same number of carbon atoms, one being an alkane, one an alcohol, and the other a carboxylic acid. Suggest the identity of the contents of each bottle, and give reasons for your explanation...
1. Write the products of the reactions below. I. HO 2. PCC 3.CH, MgBr 4. Hot 1. NaCN 2. H ,H,O 3. SOCI 4. MeOH 1. CH.CH, MgBr 2. H,H,O 3. CHỊCH,CHCO3 CH,CH,OH
24. Which of the structures are of the D configuration? 1 CHO I. CHO | III. CHO IV. HO H-C-OH H-C-OH HOC_H НО-С-н H–C-OH HO_C_H H-C-OH HOC_H CH CH CH CH,OH a. b. c. d. e. I and IV I and III I and II II and III II and IV 25. A compound, CH, NO, is hydrolyzed by strong acid, followed by neutralization to give C,H,O, and C,H.N. The CHN compound reacts with HNO, to give nitrogen gas. The...
SO 5. Complete the following reaction HC- CICH 2. CH CH.CH B. HC-6-C=CH- H2O, HgSO Hy Lindlar - C C - CH - Pd 1. BH, 2. H,02 KCN H,0 8. HC-0-2-=CH2 1. BH; HC-C-CECH i. 2. H,02 KOH, Alc., Heat BONAIRE
please explain the steps to get to the answer Find AH° for the reaction: 2 C,H,OH (1) + 0, (g) → 2 CH CHO (g) + 2 H,0 (9) GIVEN: C,H,OH (1) + 3 0, (g) → 2 CO, (g) + 3 H,0 (9) AH° = -1236 kJ 2 CHỊCHO (g) + 5 0, (g) + 4CO, (g) + 4 H,O (g) AH = -2207 kJ 2 CH OH (1) + 6 0, () — 4 CO, (g) + 6...