9. An ionized oxygen molecule (O2) at point A has charge t and moves at 2.00...

Question

Question

Answer 1

Answer #1

using work energy theorem

e E d = 0.5 m v^2

1.6* 10^-19* E* 0.75* 10^-3 = 0.5* 16* 1.67* 10^-27* 2000^2

E = 445.33 N/C

======

b)

V = Ed = 445.33* 0.75* 10^3

V = 0.334 V

Answer 2

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