Question

1. For the reaction N₂(g) + 3H₂(g) → 2NH₃(g), if 2.25 L H₂ reacts, what volume of NH₃ forms if both are at the same temperature and pressure?

2.Given the balanced reaction below:
2 C₆H₆₍g) + 15 O₂(g) $LaTeX: \longrightarrow$ ⟶ 12 CO₂(g) + 6 H₂O(g)
If 2.45 liters of benzene are consumed in this reaction, how many liters of water
can be formed? Benzene is C₆H₆

Answer 1

1.) From a balanced equation, we can say that,

22.4*3 L of H2 produces 2*22.4 L NH3.

So, 2.25 L H2 will produce NH3 = [(22.4*2)/(22.4*3)]*2.25 = 1.5L

NH3 produce = 1.5L

2.) In this we can say that,

22.4*2 L of C6H6 produce 6*22.4 L H2O.

So, 2.45 L C6H6 will produce H2O = [(22.4*6)/(22.4*2)]*2.45 = 7.35L

H2O produce = 7.35L

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