Question

Determine the pH during the titration of 11.6 mL of 0.236 M perchloric acid by 0.212 M potassium hydroxide at the following points:

(1) Before the addition of any potassium hydroxide

(2) After the addition of 6.45 mL of potassium hydroxide

(3) At the equivalence point

(4) After adding 16.0 mL of potassium hydroxide

Answer 1

Selulion acid (Perchlonic acid) bya Rdronide) nation of a streng Stong 1Befone the additon of a bage (Potassium Pota ssium Hysroride Dissocia Hon of Perchlonie aid diven belod ag H+ + CLo, Heloy 0.226 (M) 0-226(M) 0.226(M) PH of tue Solution PH o (0.226) = 0. 627 PH of le Sodution before adding kaH Soluhon is 0.627 After the adeli tion of 6.25 md of Potassium 2 Se luction Cantain 1uivalent ()a 1600 ml So, I.6ml of 6.236 (M) He toy Seluuhon Centoins 2.73tc O236 KII.6 LO00 6-45 mi of o.212(M) COH SLution Contains - O 212 1367y to 2uiv Ko G.45 Heloy KOH keloy t H20 2-7376 toao 1-3679 1.3674 The Soluion Gutoin Ex cass Per chLonic aeid (Helay- (2.737 13702 1-3679 Lo 2v Hcloy - log 63 Hon ce, After Hae addihion f 6.45 moPotassium drexide Hhe Soluhon is 2.863 Solubion, Wee PM

A+ the eauivalence Peint 3. Atthe eguiva lent Point th Solution toill Con tain NO un meulralise d acid Proton amd PH wil 6e Sim ply that sf a Soluhion 6f keloy Salt So, it wilt be pH neany egual to t 4After additing 160 mL of Po tass ium ydroi de 16 md of 0. 212 (M) KOH Soluttion Cn tains O.212 16 3.392 e2mv. KoH loD 10 00 Heloy + koH Keloy + H20 2. 7376 3.392 2.7376 10 loco The Solution Contain Excess Potaslum ydronide .. 2.7376 6544 3.392 -7 10 00 1610 ivKOH poH Log ( 3.9y O.6549 PH=14- POH 14-3.18 10.82 Theneforne Atte adliting Selution, Th PH Mee Solution is 10. 82 16-0 mL of Potasium ydroxi de