Question

You are jogging along a straight road one day at constant velocity vo when you hear the siren of an ambulance approaching from behind. The frequency you hear is f-756 Hz You stop to take a break and the frequency you hear changes to f2 765 Hz The ambulance then overtakes you and speeds away, and the frequency you hear is f3 680 Hz The speed of sound in air is Vsound 340 m/s and there is no wind. The ambulance is moving at constant velocity Vs, and the frequency of the siren at its source is fo. Answer the following questions. Us 0s Us

1. What is the speed of the ambulance v_s?

2. What is the frequency of the siren at its source f_0?

3. What is your initial speed v_o?

4. After resting a bit you start running again in the same direction as before but at half the speed. That is, our speed is vo Vo/2. What is the frequency that you will hear? 0 0s

0 0
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Answer #1

Brief:- This is an example of doppler effect with sound waves. The basic idea here is that, the apparent frequency heard by an observer or a listener changes with motion of both the source and the observer.

The apparent frequency may increase or decrease compared to the actual frequency depending on the direction of motion of source and observer with respect to each other.

Dalkr elect )の hme obferver Source velou ty of . observer Sovrce So: obserer Vfashveourte moves bm obServer etr nve noghve İ iden observer mate mdves au Sro Soure 그 웃Given § 7561/2= f。 Observer on ovin fo 310,-齿 nCeS に Zero (o 2from obte rver now ond we hwe z) g (Crot 765) 340 (765-680) 240 720 Hz Siren ot its Sovrso 720 Ha Nou, using sond340-20 756 x 220 340 -Va 70 冫ㄐ s , again a keze, Vs Posthre C.curu ,s oorng Civcr , to uass 3H0 2 40 t 20

PLEASE, feel free to ask in case of any doubts or discrepancies.

Thank You

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