Sedut Ouest. 4 (15 pts). The initial partial pressures or a gascous mixture are: PCIO.S00 am...
Sedut Ouest. 4 (15 pts). The initial partial pressures or a gascous mixture are: PCIO.S00 am PC, 0.030 atm, and Co 0.000 atm. The gases are allowed to come to equilibrium, and the partial pressure of Cl. was determined to be 0.021 atm. Calculate the value of Kp. PCIS () PCL (8) + Cl (p)
5. A mixture of H2 gas (PH2 2.05 atm), CO2 gas (Pco2 4.10 atm) and water vapor (PH20-3.28 atm) are allowed to come to equilibriurm in a closed container. The temperature is 500. K. The equilibrium represented by the equation below is established and the equilibrium partial pressure of H20 is determined to be 3.51 atm. a) Find the equilibrium partial pressures of the CO2, H2, and CO gases. CO2 (g) H2 (g) ←→ CO (g) H2O (g) + +...
Name Dalton's Law of Partial Pressures - Many gas samples are a mixture of gases. For example, air is a mixture of gases. The gases dissolved in blood make up a mixture as well. In a gas mixture, each gas exerts its partial pressure (the specific pressure contribution of the gas to the total pressure of the gas mixture). Dalton's law states that the total pressure of a gas mixture (Pita) is the sum of the partial pressures of the...
The initial partial pressures of H2, CS2, H2S, and CH4 in the fixed-volume reaction vessel were 378, 252, 68, and 54 torr, respectively. The following reaction was allowed to come to equilibrium 4H2(g) + CS2(g) ⇌ 2H2S(g) + CH4(g) Find the value of Kp given that the total pressure of the equilibrium mixture was 646 torr.
4. a) If the initial partial pressures are PNO = 126, PNOBr = 275 torr, find Qp and determine which direction the reaction proceeds. b) When a mixture of NO, Br2, and H2 reaches equilibrium at 302 K, PNO = 133 torr and PBr = 151 torr. Find PNOBr (in Torr) 5. Iodine gas and hydrogen gas are sealed in a flask and heated ti 575 K. Before they react, the inital partial pressures if I2 and H2 at 575...
At a particular temperature, Kp-0.39 for the reaction below. N204(g) 2 NO2(g) (a) A flask containing only N204 at an initial pressure of 4.8 atm is allowed to reach equilibrium. Calculate the equilibrium partial pressures of the gases. N2O4 NO2 atm (b) A flask containing only NO2 at an initial pressure of 9.6 atm is allowed to reach equilibrium. Calculate the equilibrium partial pressures of the gases. No2 (e) From your answers to parts (e) and (b), does it matter...
3a. Determine the equilibrium pressures of all the reactants and products for the equilibrium described below if you start with an initial pressure of carbon dioxide and carbon tetrafluoride each at 0.750 atm with no COF2 present. You can assume that the temperature is constant at 1550K. (12 points) 2COF2(g) CF4(g) + CO2(g) KP = 0.168 at 1550K Initial pressures: PCO2 = PCF4 = 0.750 atm; PCOF2 = 0.000 atm 3b. What is the value of KC for this reaction?...
N2(g) + 3 H2(g) ⇌ 2 NH3(g) KP = 6.78 x 105 at 298 K (determined using atm) A 7.5 x 101 L container being held at 298 K is charged with the three gases present in the above equation. Once finished, the initial partial pressure of N2 was 0.59 atm, the initial partial pressure of H2 was 0.45 atm, and the initial partial pressure of NH3 was 0.11 atm. The gas mixture was then allowed to reach equilibrium. Use...
A 8.35-L container holds a mixture of two gases at 15 ℃. The partial pressures of gas A and gas B. respectively, are 0.430 atm and 0.549 atm. If 0.210 mol of a third gas is added with no change in volume or temperature, what will the total pressure become? Number atm
A 9.65 L container holds a mixture of two gases at 15 °C. The partial pressures of gas A and gas B, respectively, are 0.390 atm and 0.777 atm. If 0.190 mol of a third gas is added with no change in volume or temperature, what will the total pressure become?