What annual interest rate do you need for an investment to be worth $4,345.47 four years in the future with semi-annual compounding if you deposit $3,300 today? Please show ALL work with finance formulas.
For compound interest, we have
A = P*(1+r)^n
Where, A = Amount received = $4,345.47
P = principal = $3,300
r = rate of interest compounded semi annually
n = period = 4 years = 4*2 periods (as semi annual compounding indicated 2 periods per year) = 8 periods
Thus,
4535.47 = 3300* (1+r)^8
Thus,
(1+r)^8 = (4535.47/3300)
1+r = (4535.47/3300)^1/8
r = (4535.47/3300)^1/8 - 1
Thus, r = 0.04055
As this is semi annual compounding, annual interest rate = 2*0.04055 = 0.0811
= 8.11%
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