A voltaic cell contains two half-cells. One half-cell contains a zinc electrode immersed in a 1.00 M Zn(NO3)2 solution. The second half-cell contains a titanium electrode immersed in a 1.00 M Ti(NO3)3 solution.
Zn2+(aq) + 2 e− → Zn(s) |
E⁰red = −0.762 V |
Ti3+(aq) + 3 e− → Ti(s) |
E⁰red = −1.370 V |
(a) Using the standard reduction potentials given above, predict
the standard cell potential of the voltaic cell.
_____ V
(b) Write the overall balanced equation for the voltaic cell.
(Include states-of-matter under the given conditions in your
answer.)
A voltaic cell contains two half-cells. One half-cell contains a zinc electrode immersed in a 1.00...
A voltaic cell contains two half-cells. One half-cell contains a titanium electrode immersed in a 1.00 M Ti(NO3)3 solution. The second half-cell contains a nickel electrode immersed in a 1.00 M Ni(NO3)2 solution. Ti3+(aq) + 3 e− → Ti(s) E⁰red = −1.370 V Ni2+(aq) + 2 e− → Ni(s) E⁰red = −0.257 V Write the overall balanced equation for the voltaic cell. (Include states-of-matter under the given conditions in your answer.)
A voltaic cell contains two half-cells. One half-cell contains a gold electrode immersed in a 1.00 M Au(NO3)3 solution. The second half-cell contains a magnesium electrode immersed in a 1.00 M Mg(NO3)2 solution. Au ** (aq) + 3 e Au(s) Ered = +1.498 V Mg2+ (aq) + 2 + Mg(s) Ered = -2.372 V (a) Using the standard reduction potentials given above, predict the standard cell potential of the voltaic cell. (b) Write the overall balanced equation for the voltaic...
A voltaic cell contains two half-cells. One half-cell contains a chromium electrode immersed in a 1.00 M Cr(NO_3)_3 solution. The second half-cell contains a nickel electrode immersed in a 1.00 M Ni(NO_3)_2 solution. Cr^3+(aq) + 3 e^- rightarrow Cr(s) E_red^degree = 0.744 V Ni^2+(aq) + 2e^- rightarrow Ni(s) E_red^degree = -0.257 V Using the standard reduction potentials given above, predict the standard cell potential of the voltaic cell. Write the overall balanced equation for the voltaic cell. (Include states-of-matter under...
A voltaic cell consists of two half-cells. One half-cell contains a chromium electrode immersed in 1.00 M Cr(NO3)3 solution. The second half-cell contains a cobalt electrode immersed in 1.00 M Co(NO3)2 solution. Cobalt plates out on the cobalt electrode as the voltaic cell runs. The beginning voltage of the cell is +0.467 V at 25°C. The standard electrode potential (standard reduction potential) of chromium at 25°C is −0.744 V. (a) Write a balanced half-reaction equation for the reaction occurring at...
A voltaic cell consists of two half-cells. One half-cell contains a chromium electrode immersed in 1.00 M Cr(NO3)3 solution. The second half-cell contains a nickel electrode immersed in 1.00 M NI(NO3)2 solution. Nickel plates out on the nickel electrode as the voltaic cell runs. The beginning voltage of the cell is +0.487 V at 25°C. The standard electrode potential (standard reduction potential) of chromium at 25°C is -0.744 V. (a) Write a balanced half-reaction equation for the reaction occurring at...
One half-cell in a voltaic cell is constructed from a silver wire electrode in a AgNO3 solution of unknown concentration. The other half-cell consists of a zinc electrode in a 1.9 M solution of Zn(NO3)2. A potential of 1.48 V is measured for this cell. Use this information to calculate the concentration of Ag (aq). E® Zn/Zn2+ = -0.763 V Eº Ag/Ag+ = 0.7994 V Concentration = Submit Answer Try Another Version 6 item attempts remaining
In a copper-zinc voltaic cell, one half-cell consists of a ZnZn electrode inserted in a solution of zinc sulfate and the other half-cell consists of a CuCu electrode inserted in a copper sulfate solution. These two half-cells are separated by a salt bridge. At the zinc electrode (anode), ZnZn metal undergoes oxidation by losing two electrons and enters the solution as Zn2+Zn2+ ions. The oxidation half-cell reaction that takes place at the anode is Zn(s)→Zn2+(aq)+2e−Zn(s)→Zn2+(aq)+2e− The CuCu ions undergo reduction...
Which of the following is a proper notation for the voltaic cell consisting of of one half-cell with a zinc electrode in 1 M Zn(NO3)2 solution and the other half-cell with a lead electrode in 1 MPb(NO3)2 solution and a KNO3 salt bridge. Pb2+(1 M) | Pb(s) || Zn(s) | Zn2+(1 M) Zn2+(1 M) | Zn(s) || Pb(s) | Pb2+(1 M) Pb(s) | Pb2+(1 M) || Zn2+(1 M) | Zn(s) Zn(s) | Zn2+(1 M) || Pb2+(1 M) | Pb(s)
Q. Consider a galvanic cell with a zinc electrode immersed in 1.0M Zn2+ and a silver electrode immersed in 1.0M Ag+. Which of the electrodes is the anode? Zn2 + 2e- --> Zn E° = -0.76 V Ag+ + e- --> Ag E° = 0.80 V
Consider an electrochemical cell with a zinc electrode immersed in 1.0 M Zn2and a silver electrode immersed in 1.0 M Agt. Zn2+ + 2e- → Zn E° = -0.76 V Agt + e- Ag E = 0.80 V Calculate Eº and AGº for this cell Calculate AGº for the reaction: 2 Zn (g) + O2 (g) + 2 H20 (1) ► 2 Zn2+ (aq) + 4 OH (aq) Reduction Half-Reaction E° (V) O2(g) + 2 H20 (1)+4 e-®4 OH(aq) +0.403...