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A voltaic cell contains two half-cells. One half-cell contains a zinc electrode immersed in a 1.00...

A voltaic cell contains two half-cells. One half-cell contains a zinc electrode immersed in a 1.00 M Zn(NO3)2 solution. The second half-cell contains a titanium electrode immersed in a 1.00 M Ti(NO3)3 solution.

Zn2+(aq) + 2 e → Zn(s)    

Ered

= −0.762 V
Ti3+(aq) + 3 e → Ti(s)    

Ered

= −1.370 V

(a) Using the standard reduction potentials given above, predict the standard cell potential of the voltaic cell.
_____ V

(b) Write the overall balanced equation for the voltaic cell. (Include states-of-matter under the given conditions in your answer.)

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Answer #1

(9) Zn2+ (aql + 20 nCS) 9 to God rod 0,762 (more) act as cathode Ti 3T (aq) + 3€ Tils) - toreda COM) -1. 370 V Eoxidation = 1

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