Question

chap08-P12 Please write the answer neatly for a thumps up, thank you!

The figure gives the acceleration of a 3.0 kg particle as an applied force moves it from rest along an x axis from x = 0 to x = 9.0 m. The scale of the figure's vertical axis is set by as = 8.0 m/s2. How much work has the force done on the particle when the particle reaches (a) x = 4.0 m, (b) x = 7.0 m, and (c) x = 9.0 m? What is the particle's speed and direction (give positive answer if the particle moves along x axis in positive direction and negative otherwise) of travel when it reaches (d) x = 4.0 m, (e) x = 7.0 m, and (f) x = 9.0 m? (7$/u) x (m) 2 4 6 8A ! (a) Number (b) Number (c) Number Units Units Units Units Units (d) Number (e) Number (f) Number Units The number of significant digits is set to 3; the tolerance is +/-3%

Answer 1

Work done = force x disp. W = FX = max ( = ma = m (ar) W = mass x ( area of the curve at disp. x) One a 17 14:5167 a) At x = 40m W mxarea 1 + area 2) = 3 X ZX 2 x 1 x 8 + 3x8 W = 84J7 b) x=7.0m W = m X grea ( + 2 + 3 - 4 - 5 :: W = 3x [ 5x1x8 + 3x8 + 3 *1**- * X1x8- 1881 W = 60 J.

X = 9m - W mx avea ( 1+2+3-4-5-6-7) :, W = 3 X + 3x8 + /*18 - _xix? -1*8 - 1X8-4xx8 W = 24 J. speed at x = 4. 0m Workdone e Total Kię of particle I mv2. W Vot 2W at x= 4.0m, W = 84 J Eva 12x84 - 7.48 mis +x-axis V3 at a = 7.0m W = 60 5 ve 2x60 - 6.32 m/s] *x-axis _V3 e 2X 60 6.32 ms +x-ax at x = 9.0 m , W = 24 J vo | 2x24 V 3 = 1 4 m/s 1 +x-axis