What is the correct electron configuration for the ion, Mo2+? Question 17 options: [Kr] 5s2 4d2...

Question

Question

What is the correct electron configuration for the ion, Mo2+? Question 17 options: [Kr] 5s2 4d2 [Kr] 4d4 [Kr] 5s2 4d6 [Kr] 4d6 [Kr] 4d5

Answer 1

Answer #1

Number of electron in Mo = 42

Electronic configuration is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d5 5s1

Explanation: d block anomaly

Since charge on Mo is +2

So, we need to remove 2 electrons

Electrons are always removed from highest number orbital

Removing 1 electron from 5s

Removing 1 electron from 4d

Final electronic configuration is : 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d4

Noble gas having lesser electron than Mo and closest to it is Krypton (Kr)

Number of electron in Kr = 36

electronic configuration of Kr is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6

So, electronic configuration of Mo in noble gas form is: [Kr] 4d4

Answer: [Kr] 4d4

Answer 2

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