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Problem 4: (a) Obtain the value of g at the top of Mt Everest, to four...
Problem 4 A square object is constructed of four identical uniform thin sticks, each of mass...
Problem 4 A square object is constructed of four identical uniform thin sticks, each of mass m and length L, attached together. This object is hung on a hook at its upper corner. If it is rotated slightly to the right and then released, at what frequency will it swing back and forth? Hints: Find the distance from the hook to the center of mass of the object. Then find the moment of inertia of each stick with respect to...
Problem 5. (12 points) A mass of 5 kg stretches a spring 4 cm when hanged...
Problem 5. (12 points) A mass of 5 kg stretches a spring 4 cm when hanged vertically. Suppose that the mass is given an addition 6 cm displacement downward and then released (at time 0), and an external force of 4-3 cos(t) N at all time (starting at time 0). In addition, suppose that the mass is in a medium that exerts viscous resistance of 3 N when the mass has a velocity of 0.4 m/s. Assume acceleration due to...
B Problem (10) 3 m 3 m The door has mass m= (2n) in kg and...
B Problem (10) 3 m 3 m The door has mass m= (2n) in kg and center of gravity at G. The door moves smoothly over a frictionless rollers at A and B. If a force F is applied to the IG door to push it open a distance 5 m to the right in 4 seconds, starting from 3 m rest. Determine the vertical reaction 1.20 m at roller A (in Newtons). Hint: first you have to find the...
y(t) = yg +ve+-0.5gt Meteor! y = 7,000 km 1) Show that a meteor, initially at...
y(t) = yg +ve+-0.5gt Meteor! y = 7,000 km 1) Show that a meteor, initially at rest (V,0 = 0) will take about 20 minutes to fall from an altitude of 7,000 km as shown in the diagram to the right. Note that the change in y is negative and you will need to convert kom into meters for the units to work out correctly. y = 0 km R= 6,371 km The calculation from problem 1) is incorrect though....
(17%) Problem 2: A uniform thin rod of mass m 1.8 kg and length L 1.7...
(17%) Problem 2: A uniform thin rod of mass m 1.8 kg and length L 1.7 m can rotate about an axle through its center. Four forces are acting on it as shown in the ngre. Their magnitudes are F = 9.5 N, F = 2.5 N, F = 14 N and F4 = 19 N. F2 acts a distance 45c F. d 0.15 m from the center of mass. |d 600 3 F Otheexpertta.com 4 20% Part (a) Calculate...
nutaud 4) Read the following and revise your free body diagram as necessary. A common confusion...
nutaud 4) Read the following and revise your free body diagram as necessary. A common confusion when drawing extended free body diagrams is how to draw the force of gravity. For a static equilibrium situation like this, you should draw a single arrow to represent the force of gravity on an extended object. The tail of this vector is placed at the center of mass of the object. It is good practice to pause at this point and think about...
Problem 4 (10 points) Astrom et a1 have presented a simplified second-order transfer function model for...
Problem 4 (10 points) Astrom et a1 have presented a simplified second-order transfer function model for bicycle dynamics as C1 Parameters defining the bicycle geometry. Schematic (a) top and (b) rear views of a bicycle The steer angle is δ and the roll angle is φ. The input is δ(t), the steering angle, and the output is Plt), the tilt angle (between the the bicycle longitudinal plane and the ground). In the model, parameter a is the horizontal distance from...
show work for these physics problem Jam Whose mass is 100 kg stands at the top...
show work for these physics problem
Jam Whose mass is 100 kg stands at the top of a 18-m-high, 120-m-long sa His skis have a coefficient of kinetic friction on snow of 0.06. He uses his poles to get then glides down. of a 18-m-high, 120-m-long snow covered slope. 1. The value closest to the normal force acting on Sam is a. 729.7 N b. 735.0 N c. 968.9 N d. 980.0 N 2. The net force acting on Sam...
I’m slightly off for part A and I dont understand what part B is asking me. Beyond confused,
I’m slightly off for part A and I dont understand what part B is
asking me. Beyond confused,
REMARKS The moment of inertia is smaller in part (B) because in this configuration the 0.20-kg spheres are essentially located on the axis of rotation. QUESTION If one of the rods is lengthened, which one would cause the larger change in the moment of inertia? the rod connecting balls two and four the rod connecting the bars one and three PRACTICE IT...
answer each problem please and show work (20%) Problem 5: You have been hired to design...
answer each problem please and show work
(20%) Problem 5: You have been hired to design a family-friendly see-saw. Your design will feature a uniform board (mass M-6 kg, length L -2.7 m) that can be moved so that the pivot is a distance d from the center of the board. This will allow riders to achieve static equilibrium even if they are of different mass, as most people are. You have decided that each rider will be positioned so...
Problem 4 A square object is constructed of four identical uniform thin sticks, each of mass m and length L, attached together. This object is hung on a hook at its upper corner. If it is rotated slightly to the right and then released, at what frequency will it swing back and forth? Hints: Find the distance from the hook to the center of mass of the object. Then find the moment of inertia of each stick with respect to...
Problem 5. (12 points) A mass of 5 kg stretches a spring 4 cm when hanged vertically. Suppose that the mass is given an addition 6 cm displacement downward and then released (at time 0), and an external force of 4-3 cos(t) N at all time (starting at time 0). In addition, suppose that the mass is in a medium that exerts viscous resistance of 3 N when the mass has a velocity of 0.4 m/s. Assume acceleration due to...
B Problem (10) 3 m 3 m The door has mass m= (2n) in kg and center of gravity at G. The door moves smoothly over a frictionless rollers at A and B. If a force F is applied to the IG door to push it open a distance 5 m to the right in 4 seconds, starting from 3 m rest. Determine the vertical reaction 1.20 m at roller A (in Newtons). Hint: first you have to find the...
y(t) = yg +ve+-0.5gt Meteor! y = 7,000 km 1) Show that a meteor, initially at rest (V,0 = 0) will take about 20 minutes to fall from an altitude of 7,000 km as shown in the diagram to the right. Note that the change in y is negative and you will need to convert kom into meters for the units to work out correctly. y = 0 km R= 6,371 km The calculation from problem 1) is incorrect though....
(17%) Problem 2: A uniform thin rod of mass m 1.8 kg and length L 1.7 m can rotate about an axle through its center. Four forces are acting on it as shown in the ngre. Their magnitudes are F = 9.5 N, F = 2.5 N, F = 14 N and F4 = 19 N. F2 acts a distance 45c F. d 0.15 m from the center of mass. |d 600 3 F Otheexpertta.com 4 20% Part (a) Calculate...
nutaud 4) Read the following and revise your free body diagram as necessary. A common confusion when drawing extended free body diagrams is how to draw the force of gravity. For a static equilibrium situation like this, you should draw a single arrow to represent the force of gravity on an extended object. The tail of this vector is placed at the center of mass of the object. It is good practice to pause at this point and think about...
Problem 4 (10 points) Astrom et a1 have presented a simplified second-order transfer function model for bicycle dynamics as C1 Parameters defining the bicycle geometry. Schematic (a) top and (b) rear views of a bicycle The steer angle is δ and the roll angle is φ. The input is δ(t), the steering angle, and the output is Plt), the tilt angle (between the the bicycle longitudinal plane and the ground). In the model, parameter a is the horizontal distance from...
show work for these physics problem
Jam Whose mass is 100 kg stands at the top of a 18-m-high, 120-m-long sa His skis have a coefficient of kinetic friction on snow of 0.06. He uses his poles to get then glides down. of a 18-m-high, 120-m-long snow covered slope. 1. The value closest to the normal force acting on Sam is a. 729.7 N b. 735.0 N c. 968.9 N d. 980.0 N 2. The net force acting on Sam...
I’m slightly off for part A and I dont understand what part B is
asking me. Beyond confused,
REMARKS The moment of inertia is smaller in part (B) because in this configuration the 0.20-kg spheres are essentially located on the axis of rotation. QUESTION If one of the rods is lengthened, which one would cause the larger change in the moment of inertia? the rod connecting balls two and four the rod connecting the bars one and three PRACTICE IT...
answer each problem please and show work
(20%) Problem 5: You have been hired to design a family-friendly see-saw. Your design will feature a uniform board (mass M-6 kg, length L -2.7 m) that can be moved so that the pivot is a distance d from the center of the board. This will allow riders to achieve static equilibrium even if they are of different mass, as most people are. You have decided that each rider will be positioned so...
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