Question

Mass: 5.40 g Molar Mass Percent Compositions ОН,0 18.015 11.18 H 88.81 O SO 64.058 50.04 S 49.95 O Ru(CO) 241.12 41.91 Ru 24.90 C 33.170 • SF 146.05 21.95 S 78.04 F CF 88.004 13.64 C 86.35 F XeF4 207.29 63.34 Xe 36.35F Mass (g) Amount (mol) Particles 0.0370 2.23 x 1022 S 1.19 0.0370 2.23 x 1022 F 4.21 0.222 1.34 x 1023 SF6 5.40 Now examine the mass of each element in an SF sample. Set the mass of SF6 to 5.4 g. What is the ratio mass F atoms, mass S atoms

Answer 1

Sfo is and of's mass of SF6 = 5-49 molas massa Sf = 146.05 g/mol moles of sf = sug - na F 0.03romol - 146.05/mot 1. We know 6 f's atom I sto molecules 7 mols of f = 0.0370 mest x 6 mol - . I motsa = 0.222 mol E mol = mass mass = molx nolas mass) - nolas mass molat mass of ff = 18.998 g/m .. mass 86 F = T2.222 makes 18.998 g/mot) 4.219 hoy maso

1 we know is atom I similably, - Is Fo molecules 1. ) 0.03zomst Sex I shols Tholst =0.0370 mols nolat mass of s= 32.065 g (mor i mass of s=(0.0370 m (32.0659 1. 186 91-19 guais atmy. - mass mass Fatoms s at me - 4.21g 1.19g - =3. Ans: - mass of Fatoms a mass of satome = 3.54