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Problem 31.29 Part A , B = 9.0x10-2 T, and V = 8.0x10 m/s. (Figure 1) What is the magnitude of the force on the proton in the

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Fo= q E = 16810-19 14x108 Foc Bq va 9x102 x 1;6710 X 8x lots = 1152 x 10-13 = 1:15 X10N F 2 JF? + Fg² = (00:4)2+(11-5)2x10-6ROTFB tane = FE - FE tano= FB 22.4 O = 62.82

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