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treatment of gold metal with BrF3 and KF produces Br2 and KAuF4, a salt of gold
Part C Find the mass of the gold salt that forms when a 73.0 - g mixture of equal masses of all three reactants is prepared.
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Reaction 2 AU+ 2BVF₂ + 2kf Brat 2 KAUFy 73g of Gold moles= 73 197 = 0.37 0.37 moles of KAUFy will be produced molar mass of Kfeel free to ask any doubt in the comment section

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