Question

A student dissolves 11. g of benzoic acid (C,H,02) in 500 ml of a solvent with a density of 1.19 g/ml. The student notices th
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Answer #1

1)

Molar mass of C7H6O2,

MM = 7*MM(C) + 6*MM(H) + 2*MM(O)

= 7*12.01 + 6*1.008 + 2*16.0

= 122.118 g/mol

mass(C7H6O2)= 11 g

use:

number of mol of C7H6O2,

n = mass of C7H6O2/molar mass of C7H6O2

=(11 g)/(1.221*10^2 g/mol)

= 9.008*10^-2 mol

volume , V = 5*10^2 mL

= 0.5 L

use:

Molarity,

M = number of mol / volume in L

= 9.008*10^-2/0.5

= 0.1802 M

Answer: 0.180 M

2)

Mass of solvent = density * volume

= 1.19 g/mL * 500 mL

= 595 g

= 0.595 Kg

use:

Molality = number of mol / Mass of solvent in Kg

= 9.008*10^-2/0.595

= 0.1514 molal

Answer: 0.151 molal

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