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Answer in units of o. 008 10.0 points A 20.7 kg person climbs up a uniform ladder with negligible mass. The upper end of the ladder rests on a frictionless wall. The bottom of the ladder rests on a floor with a rough surface where the coefficient of static friction is 0.4. The angle between the horizontal and the ladder is θ . The person wants to climb up the ladder a distance of 1.8 m along the ladder from the ladders foot. der and e to the ground im e to the 1.8 m 20.7 kg is cor- μ 0.4 What is the minimum angle θin (between the horizontal and the ladder) so that the person can reach a distance of 1.8 m without having the ladder slip? The acceleration of gravity is 9.8 m/s2 Answer in units ofo.
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Nz 乙 Ni = 81.14 N te 81-14 x l4

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