What is the pH of a buffer with 0.15M HN3 and 0.20 M LiN3? Ka= 4.5x10-4
What is the pH of a buffer with 0.15M HN3 and 0.20 M LiN3? Ka= 4.5x10-4
1. What is the pH of a buffer consisting of 0.30 M CH3COOH & 0.20 M NACH:COO? Ka= 1.8 x 10-5 2. What is the pH of the buffer with 0.10 M NH3 and 0.20 M NH4NO3? Kl = 1.8 x 10-5 3. What is the pH of a buffer formed from combining 10 mL of 0.250 M HCl with 90 mL of 0.150 M NH3? (K = 1.8 x 10-) 4. Calculate the pH of the solution that results...
1.) a buffer solution is 0.453 M im HNO2 and 0.339 M in NaNO2. If Ka for HNO2 is 4.5x10^-4, what is the pH of this buffer solution? pH = ???? 2.) A buffer solution is 0.373 M in H2C2O4 and 0.303 M in KHC2O4. If Ka1 for H2C2O4 is 5.9x10^-2, what is the pH of this buffer solution? pH = ???? 3.) a buffer solution is 0.333 M in KH2PO4 and 0.248 M in K2HPO4. If Ka for H2PO4^-...
What is the pH of a buffer that is 0.95 M nitrous acid and 0.35 M sodium nitrite? (Ka = 4.5x10-4) OA. 3.23 OB. 4.24 OC. 2.91 OD. 3.78
The pH of a solution of HN3 (Ka = 1.9 x10^-5) and NaN3 is 4.86. What is the molarity of NaN3 if the molarity of HN3 is 0.016 M?
A buffer made with 150.00 mL of 0.20 M formic acid (Ka=1.8x10-4) and 250.00 mL of 0.10 M formate has a final volume of 1.0 L. What is the pH after 6.00 mL of 1.0 M HCL is added to the buffer?
1. Determine the pH of a buffer solution prepared by mixing 25.3mL of 0.35M HA (Ka= 1.6x10-5) with 15.3mL of 0.45M NaA. 2.100 mL of buffer solution that is 0.15M HA (Ka= 6.8x10-5) and 0.20M NaA is mixed with 17.3mL of 0.25M HCl. What is the pH of the resulting solution? 3. Calculate the pH of a solution made by mixing 75.0mL of 0.15M HA (Ka= 2.5x10-5) with 7.5mL of 0.75M NaOH 4. 100 mL of buffer solution that is...
26. -10.1 points 0/4 Submissions Used A buffer solution contains 0.10 mol of hydrazoic acid (HN3) and 0.43 mol of sodium hydrazoate (NaN3) in 1.70 L. The Ka of hydrazoic acid (HN3) is ka = 1.92-05. (a) What is the pH of this buffer? pH = (b) What is the pH of the buffer after the addition of 0.05 mol of NaOH? (assume no volume change) pH = (c) What is the pH of the original buffer after the addition...
Calculate the pH of 250 mL of a 0.46 M solution of HN3 before and after the addition of 0.076 mol of N3 Ka(HN3) = 0.000019 initial pH = final pH =
The Ka of hydrazoic acid (HN3) is 1.9 x 10-5 at 25°C. What is the pH of a 0.35 M solution of HN3? 2.59 5.23 2.41 O 1.14
100 mL of buffer solution that is 0.15M HA (Ka= 6.8x10-5) and 0.20M NaA is mixed with 29.7mL of 0.25M HCl. What is the pH of the resulting solution?