1) The percentages are:
% K = 19%
% P = 17%
2) a) The lost mass is calculated:
m lost = 10 mL * (0.023 g / 100 mL) = 0.0023 g
b) The percentage is calculated:
% Lost = 0.0023 * 100 / 5.02 = 0.05%
4) The molar mass of the precipitate formed is 245.3 g / mol.
If you liked the answer, please rate it in a positive way, you would help me a lot, thank you.
Pre-Lab Study Questions Name Gravimetric Analysis: The Determination of the % Phosphorus in Plant Food 1....
an introduction to chemistry lab Pre-Lab Study Questions 1. How can the presence of an ion in a solution be detected? ไป dedeed by a lame the ions undec gp color changes By com paring knoum olion o a unKnown vo Can co ure he color ehanges in he lame If a reaction produces an insoluble salt, what will you notice happening in the test tube? 2. So,It wany saヅdissolved and tt a, precipitate oat, solut kan bep eadind on...
Purpose: To calculate the amount of AgNO3 present in an unknown solution of water through the process of gravimetric analysis with NaCl. Background: Have you ever had difficulty lathering soap or find that the scum in your shower constantly needs to be removed? These are signs of “hard water.” Soap does not lather well in hard water because metal ions, such as Ca2+, form precipitates, creating “soap scum.” A precipitate is an insoluble compound that forms when soluble ions in...
10. Write a one-page summary of the attached paper? INTRODUCTION Many problems can develop in activated sludge operation that adversely affect effluent quality with origins in the engineering, hydraulic and microbiological components of the process. The real "heart" of the activated sludge system is the development and maintenance of a mixed microbial culture (activated sludge) that treats wastewater and which can be managed. One definition of a wastewater treatment plant operator is a "bug farmer", one who controls the aeration...