Question

A small block of mass 0.150 kg slides in a horizontal circular trajectory of radius 0.400 m at constant speed along the inside of a frictionless bowl (cross-section shown). The bowl’s surface makes an angle of 25.0° with the horizontal.

5. Find the magnitude of the normal force acting on the block.

6. Find the block’s speed.

please explain

(numbers 5-6) A small block of mass 0.150 kg slides in a horizontal circular trajectory of radius 0.400 m at constant speed along the inside of a frictionless bowl (cross-section shown). The bowl's surface makes an angle of 25.0° with the horizontal. 5. Find the magnitude of the normal force acting on the block. a) 1.36 N b) 1.39 N c) 1.50 N - - d) 1.62 N (25 e) 1.66 N - --> 6. Find the block's speed. a) 1.27 m/s b) 1.37 m/s C) 1.47 m/s d) 1.57 m/s e) 1.67 m/s

Answer 1

Date: Page: Solution :- Rioso AR (5) R= normal force Ruoso = mg Roino R = mg Here, m= 0.15 kg, o= 25° R = 0.1589.8 cos 25° R = 1062 N Arewer = (d) Now, 8= radius mu? - Rino v= qRsino sin 25° O.UX 1.62 X 0.15 VE 1- 35m k 1.37mls. Ary were