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For the reaction 2 NO(g) + O2(g) 2 NO2(g) G° = -71.1 kJ and S° =...

For the reaction 2 NO(g) + O2(g) 2 NO2(g) G° = -71.1 kJ and S° = -146.5 J/K at 294 K and 1 atm. This reaction is (reactant, product) favored under standard conditions at 294 K. The standard enthalpy change for the reaction of 1.67 moles of NO(g) at this temperature would be kJ.

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Fr dhe Reaethien 2 No lA)+ 21a) 2 No La) A40 AS -146-5 k T2 294 K we know, AG AH TAS for the aboe Aeac tm 2 molas f No) A49-Standard En daal by change lau) fr 1:61 mly 95.36 lef AHi- as.361eT∆H° for 1.67 moles =95.36kj

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