here,
charge , q = - 6* 10^-9 C
s = 0.5 m
a)
the potential at A , Va = 30 V
let the potential at B be Vb
using work energy theorm
work done by potential = kinetic energy gained
(Vb - Va ) * q = 3 * 10^-7
(Vb - 30) * 6 * 10^-9 = 3 * 10^-7
Vb = 80 V
the potential at B is 80 V
b)
the electric feild , E = (Vb - Va) /s
E = ( 80 - 30) /0.5
E = 100 N/C
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