Homework Answers
A skier with mass 64.0 kg starts at rest at the top of an 842 m...
A skier with mass 64.0 kg starts at rest at the top of an 842 m long ski slope, which makes an angle 13.0 ∘ with the horizontal. A typical coefficient of friction between skis and snow is 5.20×10−2. skiers don't go straight down the hill- they zigzag back and forth. Even though they still end up at the bottom of the hill, they've lost more energy to friction because friction is a non-conservative force. Let's say due to zigzagging,...
A skier at the top of a hill has a velocity of 6m/s and when she...
A skier at the top of a hill has a velocity of 6m/s and when she reaches the bottom her velocity is 13 m/s. Ignore friction, and find how tall the hill was.
A skier approaches the base of an icy, frictionless hill with a speed of Vo. As...
A skier approaches the base of an icy, frictionless hill with a
speed of Vo. As the skier travels up the slope, the skier slows
down. Find the HORIZONTAL and VERTICAL accelerations, NOT the
acceleration of the slope. Use the x-y axes shown with horizontal
rightward and vertical upward as positive. The initial velocity, Vo
= 10.2 m/s The angle of the hill, b = 15° Cannot figure this thing
out.I tried using -9.8Cos/Sin(15 but that was incorrect
3. A skier is at the top of a slope 50m (the vertical height) above the...
3. A skier is at the top of a slope 50m (the vertical height) above the base of the slope with an initial speed of 7m/s. The slope is inclined 35 degrees above horizontal and has a coefficient of kinetic friction of 0.2. What will her speed be at the bottom of the incline? a. 28.8 m/s b. 26.5 m/s c. 27.4 m/s d. 36.2 m/s e. 32.1 m/s
3. A skier is at the top of a slope 50m (the vertical height) above the...
3. A skier is at the top of a slope 50m (the vertical height) above the base of the slope with an initial speed of 7m/s. The slope is inclined 35 degrees above horizontal and has a coefficient of kinetic friction of 0.2. What will her speed be at the bottom of the incline? 28.8 m/s a. b. 26.5 m/s c. 27.4 m/s d. 36.2 m/s e. 32.1 m/s
4. A skier starts at the top of a 12 slope with a speed of 2.5...
4. A skier starts at the top of a 12 slope with a speed of 2.5 m/s. Her speed at the a Draw a sketch with labels. b. What is the length of the slope? c. How long does it take her to reach the bottom -5 m/s. Her speed at the bottom is 15 m/s. Sketch Known information Calculations
A 90 kg skier at the top of a 400 m icy hill slides down, through...
A 90 kg skier at the top of a 400 m icy hill slides down, through a 20 m patch of snow (µk= 0.25) and hits a 20 m long jump ramp at a 45° incline. a) (10 points) How far from the edge of the ramp does the skier land (m)? b) (5 points) How high will he get of the ground (max height (m)) ?
A skier is accelerating down a θ = 32.0° hill at a =3.51 m/s, as seen...
A skier is accelerating down a θ = 32.0° hill at a =3.51 m/s, as seen in figure below, what is the vertical component of her acceleration? Enter units. Submit Answer Tries 0/99 How long will it take her to reach the bottom of the hill, assuming she starts from rest and accelerates uniformly, if the elevation change is 337 m?
A skier is accelerating down a θ = 32.0° hill at a =3.51 m/s, as seen...
A skier is accelerating down a θ = 32.0° hill at a =3.51 m/s, as seen in figure below, what is the vertical component of her acceleration? Enter units. Submit Answer Tries 0/99 How long will it take her to reach the bottom of the hill, assuming she starts from rest and accelerates uniformly, if the elevation change is 337 m?
A 90 kg skier at the top of a 400 m icy hill slides down, through...
A 90 kg skier at the top of a 400 m icy hill slides down, through a 20 m patch of snow (uk-0.25) and hits a 20 m long jump ramp at a 45° incline. a) (10 points) How far from the edge of the ramp does the skier land (m)? b) (5 points) How high will he get of the ground (max height (m)) ? 400 m 20 m 45° X 20 m
A skier approaches the base of an icy, frictionless hill with a
speed of Vo. As the skier travels up the slope, the skier slows
down. Find the HORIZONTAL and VERTICAL accelerations, NOT the
acceleration of the slope. Use the x-y axes shown with horizontal
rightward and vertical upward as positive. The initial velocity, Vo
= 10.2 m/s The angle of the hill, b = 15° Cannot figure this thing
out.I tried using -9.8Cos/Sin(15 but that was incorrect
3. A skier is at the top of a slope 50m (the vertical height) above the base of the slope with an initial speed of 7m/s. The slope is inclined 35 degrees above horizontal and has a coefficient of kinetic friction of 0.2. What will her speed be at the bottom of the incline? a. 28.8 m/s b. 26.5 m/s c. 27.4 m/s d. 36.2 m/s e. 32.1 m/s
3. A skier is at the top of a slope 50m (the vertical height) above the base of the slope with an initial speed of 7m/s. The slope is inclined 35 degrees above horizontal and has a coefficient of kinetic friction of 0.2. What will her speed be at the bottom of the incline? 28.8 m/s a. b. 26.5 m/s c. 27.4 m/s d. 36.2 m/s e. 32.1 m/s
4. A skier starts at the top of a 12 slope with a speed of 2.5 m/s. Her speed at the a Draw a sketch with labels. b. What is the length of the slope? c. How long does it take her to reach the bottom -5 m/s. Her speed at the bottom is 15 m/s. Sketch Known information Calculations
A skier is accelerating down a θ = 32.0° hill at a =3.51 m/s, as seen in figure below, what is the vertical component of her acceleration? Enter units. Submit Answer Tries 0/99 How long will it take her to reach the bottom of the hill, assuming she starts from rest and accelerates uniformly, if the elevation change is 337 m?
A skier is accelerating down a θ = 32.0° hill at a =3.51 m/s, as seen in figure below, what is the vertical component of her acceleration? Enter units. Submit Answer Tries 0/99 How long will it take her to reach the bottom of the hill, assuming she starts from rest and accelerates uniformly, if the elevation change is 337 m?
A 90 kg skier at the top of a 400 m icy hill slides down, through a 20 m patch of snow (uk-0.25) and hits a 20 m long jump ramp at a 45° incline. a) (10 points) How far from the edge of the ramp does the skier land (m)? b) (5 points) How high will he get of the ground (max height (m)) ? 400 m 20 m 45° X 20 m
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