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Which is the limiting reactant in the neutralization reaction of 455 mL of 3.75 M HBr with 2.00 mol of NaOH? How much of the
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Answer #1

Number of rules of HBr = (455 L) x ( 3075 mol L-1) = 10 70 mol u o v o Noot = 2:00 mol limiting reactant. Sproe Hor Pd pr des

3rd option is correct

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