You have two square metal plates with side length of 18.5 cm. You want to make...
You have two square metal plates with side length of 18.5 cm. You want to make a parallel-plate capacitor that will hold a charge of 21.5 nC when connected to a 35.8 V potential difference. Determine the necessary separation in mm. Round your answer to three significant figures.
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You have two square metal plates with side length of
18.5 cm. You want to make...
You have two square metal plates with side length of 10.50 cm. You want to make...
You have two square metal plates with side length of 10.50 cm. You want to make a parallel-plate capacitor that will hold a charge of 12.5 nC when connected to a 34.8 V potential difference. Determine the necessary separation in mm. Round your answer to three significant figures. please show your work so I can understand the process! Thank you
A = 3, B = 3, C = 11 You have two square metal plates with...
A = 3, B = 3, C = 11
You have two square metal plates with side length of (6.50+ C) cm. You want to make a parallel-plate capacitor using Mylar as a dielectric (dielectric constant, k 3.2) that will hold a charge of (12.5 + A) nC when connected to a (34.8 B) V potential difference. Determine the necessary separation in mm between the plates (thickness of the Mylar). Round your answer to two significant figures.
A = 3, B = 3, C = 11 You have two square metal plates with...
A = 3, B = 3, C = 11
You have two square metal plates with side length of (6.50 C) cm. You want to make a parallel-plate capacitor using Mylar as a dielectric (dielectric constant, k 3.2) that will hold a charge of (12.5 A) nC when connected to a (34.8 B) V potential difference. Determine the necessary separation in mm between the plates (thickness of the Mylar). Round your answer to two significant figures.
There are two square metal plates with side lengths of 24.5cm. I want to make a...
There are two square metal plates with side lengths of 24.5cm. I want to make a parallel plate capacitor that will contain a charge of 20.5nC when it is connected to a 37.8 V potential difference. What is the necessary separation in mm?
A parallel-plate capacitor is made by using two square plates with a side length of 1.6...
A parallel-plate capacitor is made by using two square plates with a side length of 1.6 cm, spaced 4.7 mm apart. It is connected to a 12 V battery. (a) What is the capacitance? (b) What is the charge on each plate? (c) What is the electric field between the plates? (d) If the battery is disconnected and then the plates are pulled apart to a separation of 9.4 mm, what are the answers to parts (a) through (d)? (e)...
A parallel plate capacitor is constructed with square metal plates of side length S. They are...
A parallel plate capacitor is constructed with square metal plates of side length S. They are 1 mm apart. Find the value of S if the capacitance of the device is 1 farad. Do you think your answer is reasonable? Explain.
A parallel-plate air capacitor is made by using two square plates, 13 cm × 13 cm...
A parallel-plate air capacitor is made by using two square plates, 13 cm × 13 cm each, spaced 3.7 mm apart. It is connected to a 10-V battery. If the capacitor remains connected to the battery and the plates are pulled apart to a separation of 7.7 mm . a) What is the new capacitance? b) What is the new charge on each plate? c)What is the new electric field between the plates? d) What is the new energy stored...
Two charged, square plates, separated by a distance of 22.8 cm and each with a side...
Two charged, square plates, separated by a distance of 22.8 cm and each with a side length of 37.4 cm, make up a parallel-plate capacitor. The electric field inside the plates is 2.00×103 N/C. If the charge is doubled, what would the electric field inside the plates become?
consider a square parallel plate capacitor with side 20 cm and a separation d = 8...
consider a square parallel plate capacitor with side 20 cm and a separation d = 8 mm. a dielectric ... Your question has been answered Let us know if you got a helpful answer. Rate this answer Question: Consider a square parallel plate capacitor with side 20 cm and a separation d = 8 mm. A dielectri... Consider a square parallel plate capacitor with side 20 cm and a separation d = 8 mm. A dielectric block of constant k...
Two circular metal plates with radii of 10.0 cm are separated by a distance of 0.200...
Two circular metal plates with radii of 10.0 cm are separated by a distance of 0.200 mm. They are connected to the terminals of a car battery (treat as 12.0 V). (d) You now return the plates to their original separation and allow a long time to go by so that the capacitor is fully charged. You then disconnect the battery from them. Again, using insulated plates, you pull the plates apart until they are separated by 0.400 mm. Now...
A = 3, B = 3, C = 11
You have two square metal plates with side length of (6.50+ C) cm. You want to make a parallel-plate capacitor using Mylar as a dielectric (dielectric constant, k 3.2) that will hold a charge of (12.5 + A) nC when connected to a (34.8 B) V potential difference. Determine the necessary separation in mm between the plates (thickness of the Mylar). Round your answer to two significant figures.
A = 3, B = 3, C = 11
You have two square metal plates with side length of (6.50 C) cm. You want to make a parallel-plate capacitor using Mylar as a dielectric (dielectric constant, k 3.2) that will hold a charge of (12.5 A) nC when connected to a (34.8 B) V potential difference. Determine the necessary separation in mm between the plates (thickness of the Mylar). Round your answer to two significant figures.
A parallel-plate capacitor is made by using two square plates with a side length of 1.6 cm, spaced 4.7 mm apart. It is connected to a 12 V battery. (a) What is the capacitance? (b) What is the charge on each plate? (c) What is the electric field between the plates? (d) If the battery is disconnected and then the plates are pulled apart to a separation of 9.4 mm, what are the answers to parts (a) through (d)? (e)...
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