Homework Answers
1) mass of the gas = 22.100-21.303 = 0.797 g
volume of the bulb = 4.4 L
density (d) = mass/volume = 0.797/4.4 = 0.181 g/L
2) from ideal gas equation
PV = nRT
number of moles of gas n = PV/RT = (0.075*4.4)/(0.0821*297.7) = 0.0135 mol
3) number of moles n = weight of gas/molar mass of gas
so molar mass of the gas = weight of the gas / number of moles = 0.797/0.0135 = 59.04 g//mol
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