Question

i have test in 2hrs. please answer. thank you

AH° = -113.2 kJ AH° = ?? 4. Consider the following thermochemical equation: 2NO(g) + O2(g) → 2 NO2 (g) Calculate AHⓇ for the reaction below: 4 NO2 (g) — 4NO(g) + 202 (g) A. +334.5 kJ B. -146.19 kJ C. +226.4 kJ D. +192.38 kJ E. -509.2 kJ

Answer 1

Hi,

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Given reaction:

2NO(g) + O2(g) + 2NO2(g)

: ΔΗ = -113.2 kJ

Reversing the above reaction will change the sign of change in enthalpy:

2NO2(g) + 2NO(g) + O2(g)
  
:ΔΗ =-ΔΗ =-(-113.2 kJ)

... ΔΗ = 113.2 kJ

Multiplying the above reaction will give our required reaction, doubling the reaction will also doubles change in enthalpy:

Required reaction:

4NO2(g) + 4NO(g) +20269)

ΔΗ; = 2x ΔΗ = 2x 113.2 kJ

:. ΔΗ = +226.4 kJ

So the correct option is Option (C) +226.4 kJ

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