Question

1st attempt Part 1 (0.5 point) See If light has a wavelength of 615 nm, what is the energy of this light expressed with units of kJ/mol? kJ/mol Part 2 (0.5 point) A beam of radiation has an energy of 3.27x102 kJ/mol. What is the wavelength of this light? nm

Answer 1

C = 3*10^8 m/s

$\lambda$    = 615nm = 615*10^-9m

h = 6.625*10^-34 J-sec

E   = hv

     = hC/$\lambda$

     = 6.625*10^-34*3*10^8/(615*10^-9)

      = 3.23*10^-19J/photon

   1mole = 6.023*10^23 photos

1photon = 6.023*10^23/mole

E   = 3.23*10^-19 *6.023*10^23

       = 19454J/mole

        = 19.454KJ/mole >>>>answer

part-2

E    = 3.27*10^2Kj/mole

        = 3.27*10^5J/mole

       = 3.27*10^5 /(6.023*10^23)

      = 5.43*10^-19J

E   = hc/$\lambda$

$\lambda$    = hc/E

       = 6.625*10^-34*3*10^8/(5.43*10^-19)

         = 3.66*10^-7 m

        = 366*10^-9 m          [ 10^-9 m = 1nm]

       = 366nm >>>answer