Question

Chapter 27, Problem 068 A 1.08 mF capacitor with an initial stored energy of 0.132 ) is discharged through a 1.93 M22 resistor. (a) What is the initial charge on the capacitor? (b) What is the current through the resistor when the discharge starts? At time t = 605 s, find (c) the potential difference VC across the capacitor, (d) the potential difference VR across the resistor, and (e) the rate at which thermal energy is produced in the resistor. (a) Number Units (b) Number Units a (c) Number (d) Number Units Units Units (e) Number Click if you would like to Show Work for this question: Open Show Work

Answer 1

The solution for this question is given below

Giren, C = 1.08 X10-3F. 0 - 0 ° (9) J , R = 1.93X1062 (a) Initial charce can be found' by: Vir di² mo-6 A: >> Q; - 12.C.Vi V2x1•08x10-3x 06132 -> Ti = 169 X10-26 (6) Initially, voltage of capacitor, Vi = Q = 1.6 9 X10 - 15.65 V. . C 1.088 10-3 So, current through resistor when the discharge starts, Ii --Vi Ii =-15.65 793 viac = 8.1 x 10-6A.7 (C) t =6055 Ve=Vi e-t/Rc - Về - 156 5 X 4-665/'• 088/D3x1.93x10% ) V = 11.71 (d) VR = R X IP = RxI; e-tire > VR = 1.93X100X(-8.1810 Je-l605/ -1605/1.08 X10-3x1.93X106) → VR = - 11.71V1

(e) Rate at which thermal energy is produced in the resistor, PR = VRIR := 611.71)*(-8.1X10-6)e - (60 584.08X10-3X 193X1OS) » PR = (-11071) × (-6-0681006) PR = 70.96610-6 W/

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