Homework Answers
Answer:
3.1
The reaction for the dissolution of Ca(OH)2 is "a". However, the Ca(OH)2 is relatively insoluble in water.
3.2
2HCl + Ca(OH)2 <=> CaCl2 + 2H2O Option c
3.3
Moles of HCl = (0.025/1000) x 10 = 0.00025 moles Option a
3.4
As one mole of Ca(OH)2 produce one mole of Ca2+ and two moles of OH- ions.
Answer is 0.000125
3.5
Moles of OH- will be same as moles of HCl= 0.00025
3.6 The concentration for Ca2+ will be (considering the 100% dissolution)
0.000125moles/0.015L = 0.00833 M
3.7 The concentration for OH- will be
0.000250moles/0.015L = 0.0167
3.8 The molar solubility of Ca(OH)2 will be equal to [Ca2+] = 0.00833 M
3.9 The expression for Ksp = [Ca2+][OH-]2
Please let me know. if you have any doubt by commenting below the answer.
Thanks
Add Answer to:
3.2-3.9 questions. based on number 3 statement.
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calculate the initial pH of the solution given the following
reaction.
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please explain how you got your answer.
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Part A and Part B.
Also question #3-post lab. (its circled)
A. Molar Solubility and Solubility Product of Calcium Hydroxide Trial I Trial 3 Trial 2 25.0 1. Volume of saturated Ca(OH), solution (mL) 2. Concentration of standardized HCl solution (molU/L) 3. Buret reading, initial (mL 4. Buret reading, final (mL) 5. Volume of HCI added (mL) 6. Moles of HCI added (mol) 7. Moles of OH" in saturated solution (mol) 8. (OH1, equilibrium (mol/L) 9. (Ca2 ], equilibrium (mol/L)...
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Isnt the molar solubility of Ca(OH)2 with added CaCl2 supposed to be less than the molar solubili...
isnt the molar solubility of Ca(OH)2 with added CaCl2 supposed
to be less than the molar solubility of Ca(OH)2 by itself? where
did I mess up?
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3. (2 pts) Which reaction below illustrates ligand substitution? Circle the one correct answer. a) 2...
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1. Consider the following equation: Ca(OH)2(s) + 2HCl(aq) + CaCl2(aq) + 2 H20(1).Solve the following questions...
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number 3
1 VOIULUI B) solvent C) ion (D) solute E) electrolyte 3) When the weak electrolyte HF is dissolved in water, the solution contains A) nothing B) all H+ and F-ions and no HF molecules C) only F-ions D) mostly HF molecules and a few H+ and F-ions E) all HF molecules 4) Calcium chloride reacts with sodium hydroxide to form solid calcium hydro balanced net ionic equation is_ A) CaCl2(aq) + 2NaOH(aq) - CaOH(s) + NaCl(aq). B) Ca+2(aq)...
See2354 07 Question (3 points) Watch the Chem Tour animation below on acid-base titrations. Then, answer the questions about the following reaction: Ca(OH)2(aq) +2HCl(aq) +CaCl(aq) + H20(1) An aqueous solution of CaOH) with a concentration of 0.167 Mwas used to titrate 25.00 mL of aqueous HCI. 14.43 mL of the CaOH) was required to reach the endpoint of the titration ACID-BASE TITRATIONS Introduction A titration is the sequential addition of reactant to a solution containing other reactants. In an acid-base...
calculate the initial pH of the solution given the following
reaction.
Ca(OH)2 -> Ca2+ + 2OH- with ksp= 1.3 x 10^-6
please explain how you got your answer.
15) (5 pts) Calculate the initial pH of the solution given the following reaction and equilibrium information below: Ca(OH),(s) = Ca2+ (aq) + 20H- (aq) with Ksp = 1.3 x 10-6 A) 8.2 B) 10.3 C) 11.8 D) 12.1 E) None of these are correct + Ann
Part A and Part B.
Also question #3-post lab. (its circled)
A. Molar Solubility and Solubility Product of Calcium Hydroxide Trial I Trial 3 Trial 2 25.0 1. Volume of saturated Ca(OH), solution (mL) 2. Concentration of standardized HCl solution (molU/L) 3. Buret reading, initial (mL 4. Buret reading, final (mL) 5. Volume of HCI added (mL) 6. Moles of HCI added (mol) 7. Moles of OH" in saturated solution (mol) 8. (OH1, equilibrium (mol/L) 9. (Ca2 ], equilibrium (mol/L)...
isnt the molar solubility of Ca(OH)2 with added CaCl2 supposed
to be less than the molar solubility of Ca(OH)2 by itself? where
did I mess up?
A. Molar Solubility and Solubility Product of Calcium Hydroxide メーーー Desk No. Trial 1 Trial 2 Trial 3 1. Volume of saturated CalOHD, solution (ml) 2. Concentration of standardized HCI solution (mol/L) 3. Buret reading, initial (mL) . 4. Buret reading,final(mL) 5. Volume of HCI added (mL) 6. Moles of HCl added (mol) 7....
3. (2 pts) Which reaction below illustrates ligand substitution? Circle the one correct answer. a) 2 AgNO3 (aq) + CaCl2 (aq) + 2 AgCl (s) + Ca(NO3)2 (aq) b) AgCl (s) + NaCl (aq) → Na[AgCl2] (aq) c) K3[Fe(SCN)6] (aq) + K4(EDTA) (aq) → K[Fe(EDTA)](aq) + 6 KSCN (aq) d) [Fe(H2O).](NO3)3 (aq) → [Fe(H2O)s(OH)](NO3)2 (aq) + HNO3 (aq) e) 2 K4[Fe(CN)6] + Cl2 → 2 K3[Fe(CN)6] + 2 KCI
1. Consider the following equation: Ca(OH)2(s) + 2HCl(aq) + CaCl2(aq) + 2 H20(1).Solve the following questions based on the above questions, a. What type of chemical reaction is taking place? b. How many liters of 0.100 M HCI would be required to react completely with 5.00 grams of calcium hydroxide? (5 pts) Show the work. c. If I combined 15.0 grams of calcium hydroxide with 75,0 mL of 0.500 M HCI, how many grams of calcium chloride would be formed?...
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