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If a pure R isomer has a specific rotation of – 106.0°, and a sample contains 79.0% of the R isomer and 21.0% of its enantiom

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Answer #1

specific rotation of R-Isomer [d]R = -106.00 v. s. isomer – 21.04. so Risomer = 79.04 present in R isomer is exces enantiomer

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