Question

15.Many newspapers carry a certain puzzle in which the reader must unscramble letters to form words. How many ways can the letters of EMDANGL be​ arranged? Identify the correct​ unscrambling, then determine the probability of getting that result by randomly selecting one arrangement of the given letters.

How many ways can the letters of EMDANGL be​ arranged?

Identify the correct unscramble of EMDAGL?

What is the probability of coming up with the correct unscrambling through random letter selection?

16. Many newspapers carry a certain puzzle in which the reader must unscramble letters to form words. How many ways can the letters of COUYPC be​ arranged? Identify the correct​ unscrambling, then determine the probability of getting that result by randomly selecting one arrangement of the given letters.

How many ways can the letters of COUYPC be​ arranged?

What is the correct unscrambling or COUYPC?

What is the probability of coming up with the correct unscrambling throughrandom letter selection?

19. Winning the jackpot in a particular lottery requires that you select the correct five numbers between 1 and 29 and, in a separate​ drawing, you must also select the correct single number between 1 and 18. Find the probability of winning the jackpot.

The probability of winning the jackpot is____

​(Type an integer or simplified​ fraction.)

20. Winning the jackpot in a particular lottery requires that you select the correct three numbers between 1 and 63 and, in a separate​ drawing, you must also select the correct single number between 1 and 52. Find the probability of winning the jackpot.

The probability of winning the jackpot is

​(Type an integer or simplified​ fraction.)

Answer 1

15)

There are 7 letters and they are all different, therefore

1. 7! or 7x6x5x4x3x2x1 = 5040

The first letter can be any of 7
The second letter can be any of 6 (one letter is already first)
The third letter can be any of 5 (2 letters are already first and second)
The third letter can be any of 4
The 5th letter can be any of 3
The 6th letter can be any of 2
The 7th letter is whatever is left (1)

Therefore there is 7x6x5x4x3x2x1 = 7! possible arrangements.

2.

Identify the correct unscramble of EMDANGL?

mangled

3)

What is the probability of coming up with the correct unscrambling through random letter selection?

As above but there is only one correct solution out of 5040 possible arrangements. Therefore the answer is 1/5040