Of a random sample of 205 marketing students 97 rated a case of résumé inflation as...
Of a random sample of 205 marketing students 97 rated a case of résumé inflation as unethical. Based on this information, a statistician computed for the population proportion a confidence interval extending from 0.425 to 0.521. What is the confidence level of this interval in %?
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Of a random sample of 205 marketing students 97 rated a case of
résumé inflation as...
Suppose that in a random sample of 600 registered voters in one Florida county, 87.9% strongly...
Suppose that in a random sample of 600 registered voters in one Florida county, 87.9% strongly agreed with the statement: "The State of Florida should have only one method of reading and counting ballots”. Based on this information, a statistician calculated, for the percentage of all registered voters with this view, a confidence interval extending from 85.8% to 90.0%. Find the confidence level associated with this i nterval.
In a random sample of 275 students at a university, 225 stated that they were nonsmokers....
In a random sample of 275 students at a university, 225 stated that they were nonsmokers. Based on this sample, compute a 92 % confidence interval for the population proportion of all students at the university who are smokers. What is the Best point estimate, Margin of Error and Include the written statement.
What proportion of JMU students like online courses? To estimate this, a random sample of 200...
What proportion of JMU students like online courses? To estimate this, a random sample of 200 students was taken and found that 50 of them like online courses. (1) Are the assumptions for constructing a confidence interval for the population proportion satisfied? Explain.(2) Construct a 99% confidence interval for the population proportion of JMU students who like online courses.(3) What is the margin of error in (2) ?______________(4) Interpret the 99% confidence interval.
1. In a random sample of 160 lazy students, 104 believe that resume inflation is not...
1. In a random sample of 160 lazy students, 104 believe that resume inflation is not only ethical, but necessary. However, in a random sample of 200 non-lazy students, only 40 believe that resume inflation (ethical or not) is necessary. (a) Construct a 90% confidence interval for the difference between the proportions of the lazy students and of the non-lazy students who believe that resume inflation is necessary. (b) Find the p-value of the test HO: PL = Pn versus...
2. Suppose that a random sample of 41 state college students is asked to measure the...
2. Suppose that a random sample of 41 state college students is asked to measure the length of their right foot in centimeters. A 90% confidence interval for the mean foot length for students at this university turns out to be (21.709, 25.091). If we now calculated a 95% confidence interval, would the new confidence interval be wider than or narrower than or the same as the original? b. Suppose two researchers want to estimate the proportion of American college...
1) Question 2 options: A consumer advocate group selects a random sample of 205 snack foods...
1) Question 2 options: A consumer advocate group selects a random sample of 205 snack foods and finds that 174 of them contain more fat grams than what is indicated in the snack's nutritional information. Create a 90% confidence interval for the population proportion for snack foods that contain more fat grams that what is indicated in the snack's nutritional information. Enter the lower and upper bounds for the interval in the following boxes, respectively. You may answer using decimals...
A confidence interval was used to estimate the proportion of students at Utah Valley University who...
A confidence interval was used to estimate the proportion of students at Utah Valley University who commute from home to campus more than 10 miles a day. A random sample of 100 students generated the following 95% confidence interval: (0.588, 0.654). Using the information above, what size sample would be necessary to estimate the true proportion to within ± 0.06 using 95% confidence? 147 533 267 205
6. Trick or Treat In a survey of a random sample of 35 households in the...
6. Trick or Treat In a survey of a random sample of 35 households in the Cherry Creek neighborhood of Denver, it was found that 11 households turned out the lights and pretended not to be home on Halloween. Compute a 90% confidence interval for p, the proportion of all housholds in Cherry Creek that pretend not to be home on Halloween. What assumptions are necessary to calculate the confidence interval of part (a)? Interpretation The national proportion of all...
Suppose that 37% of ONU students have taken an online course. A random sample of...
Suppose that 37% of ONU students have taken an online course. A random sample of 200 ONU students is taken, of which 78 have taken an online course. What is the probability of obtaining a sample proportion this high or higher? There is some thought that the proportion taking online courses is no longer 37%. Based on the random sample, construct a 95% confidence interval for the proportion of ONU students who have taken an online course. ...
In a random sample of 250 students at a university, 207 stated that they were nonsmokers....
In a random sample of 250 students at a university, 207 stated that they were nonsmokers. Based on this sample, compute a 90% confidence interval for the proportion of all students at the university who are nonsmokers. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. = What is the lower limit of the 90% confidence interval? What is the upper limit of the 90% confidence interval?...
Suppose that in a random sample of 600 registered voters in one Florida county, 87.9% strongly agreed with the statement: "The State of Florida should have only one method of reading and counting ballots”. Based on this information, a statistician calculated, for the percentage of all registered voters with this view, a confidence interval extending from 85.8% to 90.0%. Find the confidence level associated with this i nterval.
1. In a random sample of 160 lazy students, 104 believe that resume inflation is not only ethical, but necessary. However, in a random sample of 200 non-lazy students, only 40 believe that resume inflation (ethical or not) is necessary. (a) Construct a 90% confidence interval for the difference between the proportions of the lazy students and of the non-lazy students who believe that resume inflation is necessary. (b) Find the p-value of the test HO: PL = Pn versus...
2. Suppose that a random sample of 41 state college students is asked to measure the length of their right foot in centimeters. A 90% confidence interval for the mean foot length for students at this university turns out to be (21.709, 25.091). If we now calculated a 95% confidence interval, would the new confidence interval be wider than or narrower than or the same as the original? b. Suppose two researchers want to estimate the proportion of American college...
In a random sample of 250 students at a university, 207 stated that they were nonsmokers. Based on this sample, compute a 90% confidence interval for the proportion of all students at the university who are nonsmokers. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. = What is the lower limit of the 90% confidence interval? What is the upper limit of the 90% confidence interval?...
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