SOLUTION :
Hose at ground level shoots water at an angle of 26º and speed of 40 m/s.
upward.
So,
horizontal speed of water, Vh = 40 cos (26) = 35.95176 m/s
vertical speed of water , Vv = 40 sin (26) = 17.534846 m/s
Building is 60 m away from the fire hose.
Time needed to reach the building
= Distance / Horizontal Speed
= 60 / 35.95176
= 1.6689 sec.
In the vertical direction gravity will decelerate the vertical speed of water
at the deceleration rate of 9.8 m/sec^2 .
So,
Height achieved in t secs. = u t - 1/2 g t^2 ; (u = Vv)
So, height achieved in 1.6689 secs.
= (17.534846)(1.6689) - 1/2 * 9.8 * (1.6689)^2
= 15.6163 = 15.62 meters approx.
Hence, water will hit the 60 meter away building at a height of 15.62 meters approx.
(ANSWER)
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