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Constants | Periodic Table Part A The total electric flux from a cubical box 23.0 cm on a side is 2550 N-m12/C What charge is enclosed by the box? ad22.6-10-9 nC enc Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining

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Answer #1

By Gauss's Law

Electric flux=Q/εo = ʃ E∙dA = 2500 Nm²/C
Area A = 6*0.23² = 0.3174m²
But we dont need Area

Q = εo * ʃ E∙dA = 8.854e-12 * 2500 = 22.1*10^-9 C
= 22.1nC

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