Question

A truck accelerates uniformly from rest to 23.0 m/s in 5.4 s along a level stretch of road. Determine the average power in W) required to accelerate the truck for the following values of the weight (ignore friction) (a) 8.00 x 10' N (b) 1.50 X 10' N Supporting Materials Physical Constants Additional Materials Reading 1/1.5 points Previous Answers OSColPhys1 8.1.001. (a) Calculate the momentum of a 1600 kg elephant charging a hunter at a speed of 7.50 m . 13000 kgm/s (b) Compare the elephant's momentum with that of a 0.0400 kg bullet fired at a speed of 600 m/s. 5625 (momentum of elephant / momentum of bullet) (c) What is the momentum of the 90.0 kg hunter running at 7.50 ms arter missing the elephant? X kg M's Additional Materials - 1 points osColPhys1 8.1.005. Arunaway train car that has a mass of 10,000 kg travels at a speed of 5.0 m/s down a track. Compute the time required for a force of 1900 N to bring the car to rest.

Answer 1

Aut meurt velocing to time to after I = 5.4 gee velocity = 23.0 MIS distance d = velocity & Time - 23.045.4 M AB d: 24.2m b = 8 x 103N . w = ? Work done = Forcey distance : 8 x ( x 124: 2 Năm Iw : 993.6 kw ] © F = 1.50 X 109 w = 1.50 X 107 X 184.2 Nam Iw = 18 63 kw [ Rw = 1000w] ② 0 m = 1800kg = 7.50 mis momentum p = M XV = 180087.50 P = 13500 kg mis © M = 0.0400 kg v = 600 MIS P = oloyoo x 600 - 24Kg Ms.

© m = p - go kg N = 7.50 M15 MV - gox7.50 = 675 kg M/S F = 1900 N Ninitial to A Final = ? f = ma m= 10000kg y = 5M15 Froi i tinitiu = ls . - Ma a = d = 4 - Vi & -ti F-m , vf - Viq. PF -ti) (64) = 5x100 100 19 to = 27.375ee