Question

5. Two cars initially separated by 1000 m are traveling away from each other. Car A is moving at 20 m/s and is accelerating at 4 m/s'. Car B is moving at 10 m/s and is accelerating at 6 m/s. About how far (in meters) will Car A have traveled when the cars are 4000 meters apart? 6. A sailboat leaves a harbor and sails 1.8 km in the direction 65° south of east, where the captain stops for lunch. A short time later, the boat sails 1.1 km in the direction 15° north g fhom he anhor

Answer 1

By concept of Relative Speed velocity of A with respect to B: of A w.r.t acceleration to B V_A/B = 20 + 10 = 30 m/s a_A/B = 10 m/s^2 initial distance = 1000 m final Distance b/w car = 4000 m Displacement = 3000 meters S = 3000m: V = 30 m/s a = 10 m/s^2 3000 = 30 t + 1/2 times 10 times t^2 times = > 600 = 6 t + t^2 t^2 + 6 t - 600 = 0 t = 21.68 seconds After t = 21.68 seconds car �A� travelled: S_A = Ut + 1/2 a_A t^2 = (20 times 21.68) + 1/2 times 4 times 21.68^2 S_A = 1373.65 meters