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3) The pressure in the core of Jupiter is about 4.8 x 1012 Pa. At this pressure, water will not stay in liquid form, but if i
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Solution- Volume of water = 1 Yaes of boater Deniity of water Density of water on earth - 103 kg / m3 So, volume of water on

Date: Page - - - 2.2 x 100 = 4.8 * 103 1012 -e 10²-p=4 2010 x 10² p 1000 = 2181p looo 2181 p= 0.46 kg/m3 This is a lot smalleSolution- Volume of water = 1 Yaes of boater Deniity of water Density of water on earth - 103 kg / m3 So, volume of water on earth = May of water let the density of water at Jupiter's core be pe for same mals. Now, Volume of water at Jupiter core = Man of water We know, B = P - AU AU= Man of water - Mair of water 103 - Man of water ( 103-1) 10^p, ao, 2.2 X 109 = _4.88 X 1012 Man of water (203-8) May of water - 10 1103p

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