5)
moles of HCl = 50 x 1 / 1000 = 0.05
moles of NaOH = 50 x 1 / 1000 = 0.05
Can you show me how to work this problem? u 100 mol H20 e) 57 mol...
2. HCI+ NaOH H20 + NaCl AH -57 kJ/mol 100 mL of 1 M HCI and 50 mL of 1 M NAOH were mixed in a Styrofoam cup calorimeter. a. What is the system? b. What is the surroundings? c. Does the solution get hotter or colder? 3. An endothermic reaction takes place in aqueous solution. a. Does the temperature of the solution increase or decrease. b. What is the sign of AH? c. Is heat a reactant or a...
i am not sure is my answers on this lab is correct. i am
confused as fo how to find the mass of solution and moles of H+ and
OH-
Chem 1A Thermochemistry Experiment 7 Reaction 2: Heat of
Neutralization
Chem. 1A Thermochemistry Experiment 7 Data and Results: Part A M (HCI): Volume HCl(aq): h Initial Temperature: HO Reaction 2: Heat of Neutralization M(NaOH) lt 0.5 mL) Volume NaOH(aq): 22.0 " from plot) Final Temperature: 65 - D_10.5 mL) 29....
the first photo is the data I collected, can you help me fill
the second photo? third photo is information you might need to do
so.
25
ml of HCl and NaOH each
C. Heat of Reaction Original temp of HCl Onginal terms of No Oth, Final temp. of neutralized 21.5°C 21.8°C 25.2°C 22.1°C 21.6°C 25.5°C Change in temperature, AT (tako average of the original temperatures of HCl and NaOH) quo assume 50 g H20 are present) AH for the...
need help with calculations
V. Heat of reaction for NaOH (s) + HCI (aq) → Naci (aq) + H20 ()-dH(net) Direct determination Mass NaOH Moles NaOH = moles Mass of HCI solution Final temp. of solution Initial temp. of solution AT solution 30 23 C 4 C AH(net)(Direct) per mole NaOH Calculation Indirect determination Heat of dissolution of NaOH (s) [AH(diss)] Mass NaOH Moles NaOH moles Mass of water Final temp. of solution Initial temp. of solution AT solution AH(diss)-...
Im
having trouble figuring out how to do this question especially
since "formed" is emphasized on. its the bottom one thats giving me
trouble.
H-17 Practice Questions: Reaction Enthalpy Question 1: Neutralization Enthalpy Results (NaOH + HCI) Volume of NaOH (c = 1.25 mol L ) Volume of HCI (c = 1.00 moll) 6.9 un (use correct sign) Amount of limiting reagent (specify reagent) Astration per mole of water formed HCL CV-n mol kl mol 1. Calculate the heat of...
Thermodynamics: heat of reaction, temp change, ans enthalpy of
reaction. Please help me! I am so lost! thank you!
Lab Partners: Name For our calculations, we will assume that the heat capacity of each solution is 4.18J/g.c, because aqueous solutions are in fact mostly water. Data and Results Sheet Initial Initial Expt. # moles moles он Theo. Yield of H20 formed Limiting Reactant T (°C) Mass of solution (B) ΔΗ (kl/mol) T (C) AT (°C) q absorbed by solution 0...
can you do the 7 and 9 ? can you also show and explain
me step by step?
D. 49.6 kJ E. 57.3 kJ 7. Butane (C4H10) undergoes combustion in excess oxygen to generate gaseous carbon dioxide and water. Given AH° [C4H10(g)] = -124.7 kJ/mol, AH° [CO2(g)] = -393.5 kJ/mol, AH [H2O(g)] = -241.8 kJ/mol, how much energy is released (kJ) when 8.30 g of butane is burned? Combustion of butane: 2 CH2(g) + 13 O2(g) → 8 CO2(g) +...
can someone show me how to do the work and explain it to me
TIEM210-W03, Fall 2019 Prof. J. Fiorito 13. What is the rate limiting step in the following reaction? (CH3)3CCI + H2O - (CH);COH + HCI A) (CH3)3CCI -- (CH3)3C' + cr B) (CH3)3C + H2O - C) (CH3),C-OH + H20 - D) H0+ + cr H (CH3)3C-OH, (CH3),COH + H30 Cl + H20
moles of h3o neutralized with oh and heat of neutralization
per mole of h3o neutralized
Lab 6 Chemistry 117 University of Massachusetts Boston Part 2: Heat of Neutralization Data a. Exact volume of 1.00 M HCl(aq) (-50 mL) b. Exact volume of 1.00 M NaOH(aq) to be added (30-40 mL) c. Moles of NaOH d. Assuming 1.00 mL = 1.00 g, mass of solution produced on mixing e. Heat capacity of calorimeter, Coal f. Initial temperature, Ti g. Final temperature,...
help me solve 1-3
Input Data Reactant Mg MgO Mass (9) 2300 104 Volume (mL) 100.0 1000 AT (C) 10.4 9.6 Calculated Enthalpies of Reaction Mg(s) + 2 HCl(aq) --> MgCl, (aq) + H29) AH = -459.83 kJ/mol MgO(s) + 2 HCl(aq) -> MgCl2(aq) + H20(0) AH = -155.66 kJ/mol Mg(s) + 4029) -> Mg(s) AH = -589.99 kJ/mol Problem: Solve for the following enthalpy changes 1) When 6.07 g NaOH(s) is reacted with 200.0 mL 0.759 M HCl(aq), the...