Question

The answer is A, but could someone explain why.

H) Answers B and C are correct (6) Which of the following aqueous solutions will have the highest freezing point? A) 0.250 m CH3CH2OH B) 0.180 m AlPO4 9 0.060 m Al2(SO4)3 D) 0.095 m (NH4)3PO4 E) 0.100 m MgCl2

Answer 1

Answer! ott =Kfm BTf depression in freez ing point Freezing point depression is directly related to the molality of solute particle. 0.250m CH 3 CH 2 OH = 0.25om particle 4 covolent 0.1 domAIPO 4 = 0.100 m Al3+ +0.180 m por = 0.360 m particles. 0.060m Al2(504)3 = 0: 060X2 mA13++ 0.060X 3m so 43- = 0.3om particles → = 0.095M(NH4) Po 4 = 0.095x3m NHatt 0.095 m Po43- = 0.38 m parlide - 0.100 m Mach ² 0 100m Mg 2+ + 2x01comer = 0.300 m particles so lowest depression in freezing porint is in 0.250 m CH2 CH₂04 [AT by which it has hight freering point. please rate it