Homework Answers
1st calculate the energy required
Given:
m = 150 g
C = 4.18 J/g.oC
Ti = 20 oC
Tf = 70 oC
use:
Q = m*C*(Tf-Ti)
Q = 150.0*4.18*(70.0-20.0)
Q = 31350 J
Given:
lambda = 10.8 cm = 0.108 m
1st calculate energy of 1 photon
use:
E = h*c/lambda
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(0.108 m)
= 1.841*10^-24 J
number of photon = total energy/energy of 1 photon
n = 31350.0/1.841*10^-24
= 1.703*10^28
Answer: 1.70*10^28 photons
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