Question

Calculate the mass of MgCO₃ precipitated by mixing 10.00 mL of a 0.200 M Na₂CO₃ solution with 5.00 mL of a 0.0550 M Mg(NO₃)₂solution.

Answer 1

Millimoles of Na2CO3 = 10 mL * 0.2 mmol/mL = 2 mmol

Millimoles of Mg(NO3)2 = 5 mL * 0.055 mmol/Ml = 0.275 mmol

The millimoles of MgCO3 produced = 0.275 mmol

Therefore, the mass of MgCO3 precipitated = 0.275 mmol * 84 g/mol = 0.0231 g