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4. A square wire circuit has a 1.0 A current flowing as shown. If the wire is centered on the origin in the xy-plane and the

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given I= 1.0A L = 20.0mm -0.02 m op = 2 mm = 0.002m L-20mm we will calculate the magnetic field produced by each segment : Se2 Segment BC PE = -0.002 -0.008 mar B Ec= L = o.olm BE: y = 0.01 m tand - EC -0.008 = 1.25 = 2 = tan (1.25) = 51.34 PE tanß=O tand- Dia 2 0.01 -0.8333 = x= 39.80° 0.012 PE tanß- DF = 0.01 0.8333 = B = 39.80 PE 0.0) 2 magnetic field B4 - Mo I (sindSo No = 4TX 107 T B- 45X10 X 46.21 (B= 5.8x105 T o inside the paperif you have any confusion then please ask me in the comment box.

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