At equilibrium:
PbI2 <----> Pb2+ + 2 I-
s 2s
Ksp = [Pb2+][I-]^2
1.4*10^-8=(s)*(2s)^2
1.4*10^-8= 4(s)^3
s = 1.5*10^-3 M
Now use:
[I-] = 2s
= 2*1.5*10^-3 M
= 3.0*10^-3 M
Answer: E
is this answer e? 2. In a solution prepared by adding excess Pbl2(S) [Kgp = 1.4...
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