Question

Question 3 in heating and cooling, 9 = Not yet answered Select one: ATIC Marked out of 1.00 P Flag question O -ΡΔν • CVAT O m c ΔΤ Question 4 Physical changes occur at constant Not yet answered Marked out of 1.00 Select one: • entropy O time p Flag question temperature O energy A change of temperature of -5°C is equivalent to a temperature change of... Question 5 Not yet answered Marked out of 1.00 P Flag question Select one: o -5K +5K O +268 K 0 -278 K

Answer 1

To calculate the amount of heat released in a chemical reaction, we une the equation = meaT. Where ay in the heat energy transferred (in joulen), min the main of liguid being heated (in gramo), in the specific heat capacity of the liquid (Joulen per gram degree celcium) and ot in the change in temportature of the liquid. So, in heating of cooling, a = me 4. The physical changen occur at Constant temperature. The physical change of a solid to liquid in called melting. At the melting point, the heat added in Woed to break the attractive forces of the solid incotead of increasing kinetic energy, and therefore the tempariature remains constant during thin physical change. Again, the physical change of liovuid to nolid in called freezing freeting involved a loon of energy in the form of heat by the liquid. liquid - nolid + energy In the core of pure crystalline substance, thin changen 1. Physical occurn at Constant tembarrature.

5. Th •The relationship between the reading of Celciun acale and Kelvin ocale in c = K-273 0 Where, c = reading of celcium scale and k= reading of Kelvin rocale Given, c= -5°c We know, c = K-273 ov, k = c +273 Oy, K = -5 + 273 Oy, K = 268 :. -5°c = 268K so, a change in temporature of -5°C in caruivalent to 268 K.