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can you explain why the answer is correct?

QUESTION 11 Given the information below calculate AHrxn for: C2Halg)+6F2g)> 2CF4 + 4HF(g) => 2HF(g ) AH°= -537 kJ ->CF4(g ) A
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26 167 + Q Holgo = Ca Halg A4 - 52.3 kg alge su o H₂ + F > 2HF AH = -537 kl. C(s) + 2 F2 CF AH = -680 kqmuutifly ear ① by - and eam @ g ② by 2 and add all of them. GH24 + 2H2 +2E+ 20+4E 4 HF + 2 CFq + ac +24, =Y (-52.3 – 2x 537 -please give thumbs up to my answer as I am in very need of that do comment for any of your doubt

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